For multiple updates with one ajax call, you might want to try sending back
a JSON response.
For example, in PHP you could do this:
<?php
$response = array(
'test1' => 'Username',
'test2' => 'Thank you for subscribing'
);
echo json_encode($response);
?>
Then, in your JS file, your ajax call would look something like this
(untested):
$.getJSON('ajax.php', {// data //}, function(response)
{
$.each(response, function(id, html)
{
$('#' + id).html(html);
});
});
-Hector
On Wed, Nov 19, 2008 at 7:32 PM, wsjquery <[EMAIL PROTECTED]> wrote:
>
> hi Mike,
> Thanks very much for the reply.
> In my php file that processes the form, how would I tell where each
> results goes. Do I place each in a div with the same id as the
> targets?
>
> Example php file
> <div id='test1'>Username</div>
>
> <div id='test2'>Thank you for subscribing</div>
>
> Thanks again for you help. Great plugin!
>
>
>
>
> On Nov 19, 9:55 pm, Mike Alsup <[EMAIL PROTECTED]> wrote:
> > > target: '#test1 #test2', // target element(s) to be updated
> >
> > Just change that to: '#test1,#test2'
> >
> > The target option takes a normal jQuery selector string.
> >
> > Mike
>
