The trouble is that the elements i'm looking for are not necessarily
direct children of the container,
so > isn't going to work. What I really need is to stop jQuery from
searching any deeper once it
finds the first <ul>, but continue the search at the same and
shallower levels.
Is there a way to do this with a $.expr[':'] plugin?
On Nov 11, 11:24 am, Klaus Hartl <[EMAIL PROTECTED]> wrote:
> That won't work. :first-child will give you *all* uls that are the
> first child of any element:
>
> <div id="container">
> <ul><!-- is first child -->
> <li>
> <ul> ... </ul><!-- is first child -->
> </li>
> </ul>
> </div>
>
> If you need the topmost ul use the ">" combinator:
>
> $('#container > u')
>
> Oh, jQuery has some documentation about
> selectors:http://docs.jquery.com/Selectors
>
> En plus knowing the spec doesn't hurt
> either:http://www.w3.org/TR/CSS21/selector.htmlhttp://www.w3.org/TR/css3-selectors/
>
> --Klaus
>
> On 11 Nov., 02:07, "Hector Virgen" <[EMAIL PROTECTED]> wrote:
>
> > Oops, it's actually $('#container ul:first-child')
> > Here's a nifty page of CSS3
> > selectors:http://www.w3.org/TR/2001/CR-css3-selectors-20011113/#selectors
>
> > -Hector
>
> > On Mon, Nov 10, 2008 at 5:06 PM, Hector Virgen <[EMAIL PROTECTED]> wrote:
> > > $('#container ul:first') should give you the first UL in the container
> > > -Hector
>
> > > On Mon, Nov 10, 2008 at 4:50 PM, Mark Gibson <[EMAIL PROTECTED]> wrote:
>
> > >> Anyone know how I can find the topmost elements of a certain type, eg.
>
> > >> Say I have several <ul> lists on a page, which in turn contain sub-
> > >> lists, and so on.
> > >> Is there a selector I can use to find all the topmost <ul> elements.
>
> > >> I've been raking my brains over this, and can't see a way with css
> > >> style selectors,
> > >> have i overlooked something?
>
> > >> Ideally I'd like to do:
> > >> $('ul:topmost')
>
> > >> or:
> > >> $('#container ul:topmost')
>
> > >> Cheers
> > >> - Mark
