you're welcome!
On Oct 22, 7:45 pm, Flavio333 <[EMAIL PROTECTED]> wrote:
> Thank You so much, after playing around with it ... it works!!!
> Thank You SO SO Much!!!
>
>
>
>
>
> RotinPain wrote:
>
> > Sure, how i could miss that!
>
> > I would assign the categories Id number (like $catid) in the Id
> > attribute of the link. Then using it as a GET parameter for the load
> > function.
> > It would give:
> > # " class="generate2"><?=$catname;?>
>
> > Then modify the function i wrote (based on the classname) using:
> > $("#myobj").load("products.php?idctg_ctg=" + $(this).attr("id") )
>
> > Here's the complete script (tested!) from your source:
> > [SCRIPT]
> > <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://
> >www.w3.org/TR/html4/loose.dtd">
> > <html>
> > <head>
> > <script src="scripts/jquery.js"></script>
> > <script>
> > $(document).ready(function(){
>
> > $(".generate2").each (
> > function () {
> > $( this ).bind (
> > "click",
> > function() {
>
> > $("#myobj").fadeOut("fast");
> > $("#myobj").slideToggle("slow");
> > $("#myobj").load("products.php?idctg_ctg=" + $(this).attr('id')
> > );
> > // id will be the one of the clicked link
>
> > }//function
> > );//bind
> > }//function
> > );//each
>
> > });
> > </script>
> > <style type="text/css">
> > <!--
> > #myobj {
> > background-color: #9999CC;
> > height: 300px;
> > width: 500px;
> > }
> > -->
> > </style>
> > </head>
> > <body>
> > <div id="myobj" align="center">
> > <?php do { ?>
> > # "><?php echo
> > $row_categorys['name_ctg']; ?> <br>
> > <?php } while ($row_categorys = mysql_fetch_assoc($categorys)); ?>
> > </div>
> > </body>
> > </html>
> > <?php mysql_free_result($categorys); ?>
>
> > But you can have a look at ricardobeat link ;)
>
> > On 21 oct, 20:57, Flavio333 <[EMAIL PROTECTED]> wrote:
> >> I tried what you said but it does not work... now both links go to the
> >> same
> >> page when clicked...
>
> >> RotinPain wrote:
>
> >> > the problem is quite simple i think, all your links have the same id
> >> > (generate2)
> >> > And the jquery function is attached to a link with this id (generate2)
> >> > So only 1 link will be responding to the function.
>
> >> > You need to use each() to attach an event to each links. Like
>
> >> > $("#generate2").each (
> >> > function () {
> >> > $( this ).bind (
> >> > "click",
> >> > function(){
> >> > //dosomething your stuff here
> >> > }//function
> >> > );//bind
> >> > }//function
> >> > );//each
>
> >> > This should normally work. But note that only one unique ID per page
> >> > is acceptable (see W3C recommandations). Better to use class name
> >> > filtering instead (there could be more than 1 time the same class on
> >> > the page but only 1 unique id).
> >> > It will only change the first line:
> >> > $(".generate2").each ( ...
>
> >> > And the HTML will looks like
> >> > # ...
>
> >> > On Oct 21, 3:56 pm, Flavio333 <[EMAIL PROTECTED]> wrote:
> >> >> Hello, I an quite new to jquery and hope someone can help with my
> >> >> problem. I
> >> >> am trying to load dynamic content in to a div(myobj)... the code i
> >> have
> >> >> so
> >> >> far is more or less as follows. it creates a box with 2 links, that
> >> it
> >> >> gets
> >> >> from 'name_ctg'. the links, are category names and when clicked
> >> should
> >> >> load
> >> >> products.php, with the right product, as was determined by the link
> >> that
> >> >> was
> >> >> clicked. I hope that make sense... now the problem is that only the
> >> >> first
> >> >> link works, the second link does nothing. I hope someone can help.
>
> >> >> <script src="jquery.js"></script>
>
> >> >> <script>
> >> >> $(document).ready(function(){
> >> >> $("#generate2").click(function(){
> >> >> $("#myobj").fadeOut("fast");
> >> >> $("#myobj").slideToggle("slow");
> >> >> $("#myobj").load("products.php?idctg_ctg=<?php echo
> >> >> $row_categorys['idctg_ctg']; ?>");
> >> >> });
>
> >> >> });
> >> >> </script>
>
> >> >> <style type="text/css">
> >> >> <!--
> >> >> #myobj {
> >> >> background-color: #9999CC;
> >> >> height: 300px;
> >> >> width: 500px;}
>
> >> >> -->
> >> >> </style>
> >> >> </head>
>
> >> >> <body>
>
> >> >> <div id="myobj" align="center">
> >> >> <?php do { ?>
> >> >> < a href="#" id="generate2" ><?php echo $row_categorys['name_ctg'];
> >> ?>
> >> >> <br>
> >> >> <?php } while ($row_categorys = mysql_fetch_assoc($categorys)); ?>
> >> >> </div>
> >> >> </body>
> >> >> </html>
> >> >> <?php
> >> >> mysql_free_result($categorys);
> >> >> ?>
>
> >> >> --
> >> >> View this message in
>
> >> context:http://www.nabble.com/can-someone-please-help-with-dynamic-links-prob...
> >> >> Sent from the jQuery General Discussion mailing list archive at
> >> >> Nabble.com.
>
> >> --
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> >> context:http://www.nabble.com/can-someone-please-help-with-dynamic-links-prob...
> >> Sent from the jQuery General Discussion mailing list archive at
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> >> - Afficher le texte des messages précédents -
>
> :clap::clap::clap::clap:
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