[jQuery] Re: There must be a better way to write this

[Erik Beeson]

How about a self calling anonymous function:

$('#folio > :first').fadeOut(function() {
$(this).next().fadeOut(arguments.callee); });
Or if you're uncomfortable with that syntax, just make a function for it:

function fadeNext() {
    $(this).next().fadeOut(fadeNext);
}

$('#folio > :first').fadeOut(fadeNext);

--Erik

On Wed, Oct 1, 2008 at 2:36 PM, ferdjuan <[EMAIL PROTECTED]> wrote:

>
> I'm trying to fade an element out, then fade it's next sibling out,
> with no predetermined amount of elements. Here is an example of how I
> have it now but with only 3 elements:
>
> function fadeEmOut(){
>        var kid = $('#folio').children();
>        kid.eq(0).fadeOut(function(){
>                kid.eq(1).fadeOut(function(){
>                        kid.eq(2).fadeOut();
>                });
>        });
> }
>
> i KNOW there is a better way to write this, I attempted using the
> each() function but it fades every element simultaneously. When
> someone writes back with the answer I'm gonna feel like a tard. Thanks!
>