I think this is the most appropiate response for this recurrent question: http://docs.jquery.com/FAQ#Why_do_my_events_stop_working_after_an_Ajax_request.3F
-- Ariel Flesler http://flesler.blogspot.com/ On Sep 26, 3:17 pm, thelemondropkid <[EMAIL PROTECTED]> wrote: > Thanks to the help I have received on this group, I am making > progress. > But now that all is working fine, the question beckons: Can jQuery do > it all over again? > > This is my code: > > <div class="box"> > <h3>some header</h3> > <img name="Image" src="photo.jpg" width="268" height="122" alt="" / > > <p>Lorem ipsum dolor sit amet.</p> > </div> > > And the jQuery: > > $(document).ready(function(){ > $("div.box> *").wrapAll('<div class="inside"></div>'); > $("div.box").append('<div class="tl"></div>'+'<div class="tr"></ > div>'+'<div class="bl"></div>'+'<div class="br"></div>'); > > }); > > The problem: > > I would have thought that jQuery would repeat the above process if I > created another div with a class of "box" below the previous one. I > was wrong! > > Is there a way to do that because I would like to create various boxes > with a class of "box" and have them all look the same. > > Thanks folks