So let say the class was named Round_gen9
I'd replace
$('.Round_gen9'').each(function() {....etc
with
$('[class^=Round_gen]').filter(function(){
return /Round_gen[0-9]+/.Round_gen( $(this).attr('Round_gen') );
}).each(function(){
var n = $(this).attr('Round_gen').match(/[0-9]+/);
// the number after 'class' for current element
});
$('n').each(function() {....etc
nothing is showing up... so I don't think this is fully right (I mean
what I wrote)
ideas??
Thanks for the help here...
jeremyBass
On Sep 23, 11:26 am, ricardobeat <[EMAIL PROTECTED]> wrote:
> Using [class^=class] is your best bet, the other option is to loop
> over all the possibilities and that is a no-go. Coupled with the
> filter function this will give you all elements with classX where X is
> a number:
>
> $('[class^=class]').filter(function(){
> return /class[0-9]+/.test( $(this).attr('class') );}).each(function(){
>
> var n = $(this).attr('class').match(/[0-9]+/); // the number
> after 'class' for current element
>
> });
>
> hope this helps.
>
> - ricardo
>
> On Sep 23, 3:08 pm, jeremyBass <[EMAIL PROTECTED]> wrote:
>
>
>
> > That is sort of what I'm aimming at... I'm looking to find the last
> > part... they are all class0 class1 class99, but I want to do something
> > for each one.
>
> > basicly tring to find .class(someNUMBER)
>
> > hope that makes more sense...
> > thanks for the help
> > jeremyBass
>
> > On Sep 23, 9:38 am, tlphipps <[EMAIL PROTECTED]> wrote:
>
> > > Not sure what you're after, but based on your example, I think you
> > > could also just do:
> > > $([class^='class']).each(function() {....etc
>
> > > That would find all elements with a class that starts with the word
> > > 'class'
>
> > > On Sep 23, 10:13 am, jeremyBass <[EMAIL PROTECTED]> wrote:
>
> > > > I think this would work... I'll try after loomin in to the "nth"
> > > > thing... thanks for the help, I'll get back soon...
> > > > jeremyBass
>
> > > > On Sep 23, 2:56 am, BB <[EMAIL PROTECTED]> wrote:
>
> > > > > Maybe you are looking for the $().filter()
> > > > > function:http://docs.jquery.com/Traversing/filter#fn
>
> > > > > I don't know if this is working:
>
> > > > > $("a[class^='myclass']").filter(function() {
> > > > > return /(myclass)[1-9]\d/.test(this.className);}).each(function() {
>
> > > > > // do something here
>
> > > > > });
>
> > > > > On 23 Sep., 05:13, jeremyBass <[EMAIL PROTECTED]> wrote:
>
> > > > > > I want to make this work...
>
> > > > > > $('.class' + [$[1-9][0-9]?] + '').each(function() {....etc
>
> > > > > > mean that the class would be .class0 or .class99 etc.
>
> > > > > > thanks for the help
> > > > > > jeremyBass
>
> > > > > > note also tried:
> > > > > > $('[class=Round_gen^[1-9][0-9]?]').each(function() {
> > > > > > $('.Round_gen'+ [(/$[1-9][0-9]?/)] +'').each(function() {
> > > > > > $('.Round_gen'+ (/$[1-9][0-9]?/)]+'').each(function() {
> > > > > > along with many others...- Hide quoted text -
>
> > > > > - Show quoted text -- Hide quoted text -
>
> > > - Show quoted text -- Hide quoted text -
>
> - Show quoted text -
