I understand. I am completely new to jQuery Development, so i think i
will post more of those beginner questions in the future. Thank you!
On 9 Jul., 22:54, Carl Von Stetten <[EMAIL PROTECTED]> wrote:
> Yavuz,
>
> That's because view source only shows the HTML as it was originally
> loaded. It does not show any DOM changes that may have been made after
> the page was initially loaded. If you have Firefox, and install the
> Developer Toolbar, the View Source pulldown on the toolbar offers "View
> Generated Source", which will show you exactly what your source looks
> like with any DOM changes included. Even better, the FireBug plugin for
> Firefox allows you to look at the source, and even watch it change in
> real time as your javascript manipulates the DOM.
>
> Carl
>
> Yavuz Bogazci wrote:
> > I seems to work, but when i show the page-source i cant see the new
> > rows. But they are visible in the browser. Its very strange.
>
> > On Jul 9, 5:31 pm, "..:: sheshnjak ::.." <[EMAIL PROTECTED]> wrote:
>
> >> You can easily remove any row that you selected, only question is if
> >> you can select apropriate rows.
>
> >> $("table tr").remove(".remove"); // removes any table rows that
> >> have class="remove"
>
> >> or like this
>
> >> $("table tr").filter(":contains(unwantedText)").remove(); //
> >> removes any row containing string "unwantedText"
>
> >> Only thing you have to watch is that your query is TR element (that
> >> was your problem, right?).
> >> If you filter by some other condition, for example children elements,
> >> then do this:
>
> >> $("table tr a.remove").parent().remove(); // query is A tag with
> >> class="remove", so you escape it with .parent()
>
> >> Same thing goes with adding rows, just use .after("<tr>Insert this
> >> row</tr>") or .before("<tr>Insert this row</tr>") methods.
