Can you Post your code? anyway $(this) gives you the DIV as Jquery object
inside of click event.
Put the same class to all your div and use some code like:
$(.yourclass).click(function(){$(this).dosomthing();});
Auriion wrote:
>
> Hi,
>
> I have 3 div's on the screen that I've also added click events to.
> These click events simply make the div you click fade out, and a
> corresponding div fade in.
>
> Now the problem is, after double checking my ID targets and experimenting
> with different combinations, that only the very last div I set to appear
> actually appears.
>
> To further the confusion, if you click the other 2 non-corresponding divs,
> it makes only that last one appear and disappear in the same way.
>
> Any thoughts? I'm completely stumped. I've even re-built the effect using
> scriptaculous with the exact same bug happening.
>
> Thanks in advance.
>
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