That would chain them all together though right, rather than fire them
all off at the same time?
I was thinking of doing something maybe like this...
var processesCompleted = 0;
var processesTotal = 4;
$("#div1").load( "scripts/generateA.php", {VAR: var}, function( ) {
processesCompleted++;
performFinal( processesCompleted, processesTotal );
});
$("#div2").load( "scripts/generateB.php", {VAR: var}, function( ) {
processesCompleted++;
performFinal( processesCompleted, processesTotal );
});
etc etc
function performFinal( completed, total ) {
if( completed == total ) {
// Do Final Work
}
}
I know it's kind of nasty, but I think it might work. It would be nice
if there was some kind of queue structure that could be passed 4 calls
and have a callback that waits for all 4 to finish...
On May 19, 4:52 pm, "Alexandre Plennevaux" <[EMAIL PROTECTED]>
wrote:
> here is how i would try it, simply using the load() function built-in
> callback parameter
>
> $("#div1").load( "scripts/generateA.php", {VAR: var} ,function(){
> $("#div2").load( "scripts/generateB.php", {VAR: var},
> function(){
> $("#div3").load( "scripts/generateC.php", {VAR: var}, function(){
> $("#div4").load( "scripts/generateD.php", {VAR: var} );
>
>
>
> } );
> }
> );
> });
> On Mon, May 19, 2008 at 10:39 PM, FreeKill <[EMAIL PROTECTED]> wrote:
>
> > Hi,
>
> > I'm thinking there is something I'm just overlooking, but I hope
> > someone can help...
>
> > I have a set of load calls that are each made at document load:
>
> > $("#div1").load( "scripts/generateA.php", {VAR: var} );
> > $("#div2").load( "scripts/generateB.php", {VAR: var} );
> > $("#div3").load( "scripts/generateC.php", {VAR: var} );
> > $("#div4").load( "scripts/generateD.php", {VAR: var} );
>
> > What I want to do is make a 5th load call, but only once the previous
> > 4 are completed. Is there a way to wrap a block of calls in a way that
> > a Callback function is called when they call complete?
>
> > I can think of some other, less optimal ways of getting this
> > accomplished, but I'm hoping someone might know how to do it the way
> > I've got it going now.
>
> > Any suggestions? Your help is appreciated...
>
> --
> Alexandre Plennevaux
> LAb[au]
>
> http://www.lab-au.com
