Oh I totally agree with you all, personally I have no problem with the weight of Jquery, but the person I'm doing this for does for some reason I don't fully understand. I'm going to send them a link to this discussion and hopefully the answers provided will work for them, and if not they can jump in to the frey :)
On Mar 5, 11:56 am, chrismarx <[EMAIL PROTECTED]> wrote: > if you load the minified or packed version of jquery, and have gzip > compression on your server (which everyone should have anyways), > jquery is only around 15kb! is that heavy? > > On Mar 5, 10:51 am, Jonny <[EMAIL PROTECTED]> wrote: > > > Ok, sorry, never mind, I guess there was just a delay in this post > > going live, sorry for my impatience :/ > > > Just to clarify, this is not really a Jquery question, but this group > > seems to be the most active one that has AJAX experts in it, so that's > > why I posted it here. I know that the people who are asking this > > question (through me) are not wanting to load a heavy js library > > (Jquery), so the advice below won't really work :( > > > - J > > > On Mar 4, 2:54 pm, "Jonny M" <[EMAIL PROTECTED]> wrote: > > > > I posted this almost an hour ago and it is still not showing up in the > > > Google Group... why? > > > > - Jonny > > > > On Tue, Mar 4, 2008 at 2:01 PM, Jonny <[EMAIL PROTECTED]> wrote: > > > > Basically, I have a JavaScript function (let's call the function > > > > "displayDiv") that ends up writing a <div> to the page. If > > > > "displayDiv" is called within a table cell, the <div> will be added > > > > and displayed in that table cell. Now, what I'm trying to accomplish > > > > is replicating this behaviour with an AJAX function (let's call the > > > > function "callAJAX") that returns HTML containing "displayDiv" and > > > > adding the code to a specific location in the page. I have tried > > > > this, problem is that the JavaScript returned from "callAJAX" was not > > > > executed. > > > > > I then did some research and tried a few things: > > > > > 1. I tried parsing out the JavaScript (displayDiv) from the > > > > returned HTML (callAJAX) and adding it to the <head> tag, which in > > > > theory, should be executed. This approach did not work for me because > > > > "displayDiv" writes a <div> to the page and from the <head> it would > > > > not know where to write the <div>. > > > > > 2. I have tried parsing out the JavaScript (displayDiv) from the > > > > returned HTML (callAJAX) and executing it with EVAL() but this would > > > > not work because the AJAX function would not know where to write the > > > > <div> created within the "displayDiv" function. > > > > > I guess what I'm hoping for is some magical piece of code that would > > > > tell the browser to parse the page again and execute the JavaScript > > > > that was added to the page by the AJAX function. > > > > > ============================ > > > > > I am posting this on behalf of a friend who is to busy today :) If > > > > anyone can tell me if this is even possible, and if so, where to go > > > > next, that would be most excellent! > > > > > Many thanks, > > > > > - Jonny
