On Dec 30, 2007, at 10:31 AM, Jeroen wrote:
On Dec 30, 2007 12:16 PM, tetrix <[EMAIL PROTECTED]> wrote:
so no one knows how to do this simple thing?
If you want to perform the same function on more then one element,
just assign a
common class and use the appropriate jQuery selector.
<img class="fade" src="x.jpg">
<img class="fade" src="y.jpg">
<img class="fade" src="z.jpg">
$(window).load( function () {
$('.fade').fadeOut(4000);
})
This should work afaik.
--
Jeroen
Or, enclose them in a containing div. Something like this, perhaps:
<div id="fade">
<img src="x.jpg">
<img src="y.jpg">
<img src="z.jpg">
</div>
and ...
$(window).load( function () {
$('#fade img').fadeOut(4000);
})
Lots of different ways. :-)
--Karl
_________________
Karl Swedberg
www.englishrules.com
www.learningjquery.com
