wrap it in [] like:
[{"job_Description":"My Job","job_Notes":"My jobs notes are here."}]
On 12/17/07, jforth <[EMAIL PROTECTED]> wrote:
>
>
> I'm running php 5.2.5
>
> in firebug I get :
>
> invalid label
>
> {"job_Description":"My Job","job_Notes":"My jobs notes are here."}
>
> On Dec 12, 1:38 pm, "Benjamin Sterling"
> <[EMAIL PROTECTED]> wrote:
> > Two quick questions:
> > what version of php are you running? I believe that zend only supports
> > php5, but I could be wrong on that.
> >
> > In firebug, what is being returned in the "response" tab?
> >
> > On 12/12/07, jforth <[EMAIL PROTECTED]> wrote:
> >
> >
> >
> >
> >
> > > I'm trying to test something here and having issues getting it to
> > > work.
> >
> > > here's my jquery script : // I should get an alert object if it works?
> > > but in firebug all I get is invalid label.
> >
> > > var url = "http://127.0.0.1/projects/micro-printing.com/projects/
> > > micro-server/index.php/client_api/test?callback=?";
> > > $.getJSON(url,
> > > function(data){
> > > alert(data);
> > > });
> >
> > > heres the json that I'm getting using zend_json:
> >
> > > {"job_Description":"My Job","job_Notes":"My jobs notes are here."}
> >
> > > and here's the php in case it helps
> >
> > > $json = new Zend_Json();
> > > $job_data = array(
> > > 'job_Description' => 'My Job' ,
> > > 'job_Notes' => 'My jobs notes are here.');
> >
> > > echo $json->encode($job_data);
> >
> > --
> > Benjamin
> Sterlinghttp://www.KenzoMedia.comhttp://www.KenzoHosting.comhttp://www.benjaminsterling.com
>
--
Benjamin Sterling
http://www.KenzoMedia.com
http://www.KenzoHosting.com
http://www.benjaminsterling.com
