Hi,
I know it's possible to use multiple $(document).ready() blocks, but it seems as though you are unable to make function calls across the different blocks, eg: $(document).ready(function() { var someFunction = function() { // some function that does stuff }; }); $(document).ready(function() { someFunction(); // a function that exists in another ready() block }); This results in a "someFunction is not defined" error. Is there a way around this, or is it not possible? Thanks, -j