Hi,

I know it's possible to use multiple $(document).ready() blocks, but it 
seems as though you are unable to make function calls across the 
different blocks, eg:


$(document).ready(function() {
      var someFunction = function() {
           // some function that does stuff
      };
});

$(document).ready(function() {
      someFunction(); // a function that exists in another ready() block
});


This results in a "someFunction is not defined" error. Is there a way 
around this, or is it not possible?

Thanks,
-j

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