[jQuery] Re: Question about comma separated selectors...

[Wizzud]

On Nov 23, 8:05 am, Jörn Zaefferer <[EMAIL PROTECTED]> wrote:
>
> How about this: $("div").filter(".one, .two")?
>
> Jörn

Nope, sorry.
That will (A) filter for '.one', then (B) filter for '.two', returning
the results of A appended by the results of B.
So...
<div id='A' class='two'></div>
<div id='B' class='one two'></div>
<div id='C' class='two'></div>
<div id='D' class='one'></div>
...gets 5 results returned in BDABC order (which, btw, I think is a
bug because the second B should not be there! - filter() should *not*
be _expanding_ the original element set, even though it's by
duplication; the returned set should be a subset of the originals and,
ideally, unique.)

The only way to do it (in current jQuery core) is, as Karl proposed,
by using a function.