Oh... I just thought of something. The hover method is actually supposed to have two functions built into it. One for over, and the other for out. I wonder if that's why you're getting the error. Should look like this:
$(".swapImages").hover(function() { var newSRC = $(this).attr("rel"); $(this).attr("src",newSRC); },function(){ // something else goes here }); -----Original Message----- From: jquery-en@googlegroups.com [mailto:[EMAIL PROTECTED] On Behalf Of Danjojo Sent: Wednesday, September 26, 2007 8:17 AM To: jQuery (English) Subject: [jQuery] g has no properties? I am doing a simple imageChange onLinkHover... I get the following error in Firebug everytime I hover over a link. But the image swaps work GREAT in all browsers. Except for the fact I see the error getting thrown in the browsers I am fine. g has no properties handleHover(Object type=mouseout target=a.showPic)jquery-svn.js (line 11) e(Object type=mouseout target=a.showPic)jquery-svn.js (line 11) e()jquery-svn.js (line 11) [Break on this error] eval(function(p,a,c,k,e,r){e=function(c) {return(c<a?'':e(parseInt(c/a)))+((c=c%a... The jQuery code to swap images is: $(".showPic").hover(function() { $("#imgLinkAct").attr("src", "images/cylinder.jpg"); }); $(".showPic2").hover(function() { $("#imgLinkAct").attr("src", "images/mgp_swap.jpg"); }); $(".showPic3").hover(function() { $("#imgLinkAct").attr("src", "images/mhc_swap.jpg"); }); $(".showPic4").hover(function() { $("#imgLinkAct").attr("src", "images/shock_swap.jpg"); }); $(".showPic5").hover(function() { $("#imgLinkAct").attr("src", "images/emy2_swap.jpg"); }); $(".showPic6").hover(function() { $("#imgLinkAct").attr("src", "images/ncy2_swap.jpg"); }); $(".showPic7").hover(function() { $("#imgLinkAct").attr("src", "images/crq_swap.jpg"); }); $(".showPic8").hover(function() { $("#imgLinkAct").attr("src", "images/clean_room_swap.jpg"); }); });