> From: Duncan
>
> But the following doesnt seem to work, how can I sort this out?
>
> for(var i = 0; i < r.length; i++){
> //alert(r[i][0])
> $(r[i][0] + ' > img').attr("src",r[i][1]); }
>
> r[i][0] has the id in it, r[i][1] has the image URL.So you are passing a selector string like this to $(): $( '60667C7C > img' )... Do you see the problem now? -Mike
