On Sep 11, 7:06 pm, "Joan Piedra" <[EMAIL PROTECTED]> wrote:
> Hmm.. Can't you clone the nodes and then just remove the _old_ parent div?
Sure, but if I'm not mistaken, using clone() is more expensive: it
creates copies of everything just to subsequently remove the
originals. By using children(), we just work with the same number of
DOM elements, just change their root. (This is based on an untested
assumption that the browser is re-linking existing items, not doing
its own internal clone-then-delete type behavior.)
In either case, though, the old parent div does get removed.
Pyro
>
> On 9/11/07, Pyrolupus <[EMAIL PROTECTED]> wrote:
>
> > On Sep 11, 3:03 pm, "Brook Davies" <[EMAIL PROTECTED]> wrote:
> > > Easy Question I think. If I use (from Jquery 1.2):
>
> > > $("#myElem").wrapAll("<div id='myDiv'></div>");
>
> > > To wrap the div 'myDiv' around 'myElem', how can I later remove that div
> > > without removing the pre-existing myElem and any other contents of that
> > div?
>
> > I'm newish to jQuery, so my syntax is not the uberest, but something
> > like the following would work:
>
> > $('div#myDiv').after($('div#myDiv').children()).remove()
>
> > In fact, it does work--I just tested it in FireBug. (I just don't
> > know the correct syntax to avoid referring to div#myDiv twice.)
>
> > Pyro
>
> --
> Joan Piedra || Frontend web developerhttp://www.justaquit.com/ ||
> http://www.joanpiedra.com/
