I know another easy way to do this with only one loop but not in jquery way.
var arrayA=[1,2,3,4,5]
var arrayB=[1,b,c,1,2]
for(var i=0;i<arrayA.length;i++)
{
if(arrayB.indexOf(arrayA[i]) != -1)
{
return true;
}
return false;
}
Michael Geary wrote:
>
>
>> From: Potluri
>>
>> Is there a jquery way to compare two arrays without looping.
>>
>> like I have an array1 [a,b,1,2,3]
>> and array2 [b,c,d,11 ].
>>
>> Is there a way like array1.compare(array2). which returns
>> true if atleast one element among the 2 arrays matches.
>
> Somebody has to loop, whether it's you or jQuery. :-)
>
> I don't know of anything built into jQuery, but if all the array elements
> are numbers or strings, it's easy to write a function that should be
> reasonably fast (certainly much faster for long arrays than the obvious
> nested loop solution):
>
> function arrayMatch( a, b ) {
> var o = {};
> for( var i = a.length; --i >= 0; )
> o[ a[i] ] = true;
> for( var i = b.length; --i >= 0; )
> if( o[ b[i] ] )
> return true;
> return false;
> }
>
> It may be possible to pick up some extra speed in the case where one array
> is much longer than the other, by choosing the shorter vs. longer array
> for
> each of the two steps. But it's not certain which would be faster - the
> short array in the first loop, or the short array in the second loop. You
> would have to benchmark it in a variety of browsers to know for sure.
>
> If the arrays may contain other kinds of objects (e.g. if a, b, etc. in
> your
> example are object references and not strings or string variables), then
> you'd have to go back to the nested loops instead of the above code.
>
> Now watch somebody make a fool of me and point to a jQuery function for
> this. :-)
>
> -Mike
>
>
>
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