On Aug 20, 2007, at 2:11 PM, Klaus Hartl wrote:
>
> Estevão Lucas wrote:
>> the way that i use is:
>> $( "body" ).append("<div class='testDiv'></div>").find( ".testDiv" );
>> Thus the created element will be returned
>
> I usually code that like the following to save one expensive search
> operation and code duplication like the class name:
>
> var div = $('<div class="test"></div>').appendTo(document.body);
>
Ha! Klaus, this is getting scary. :-) How many times do we post a
virtually identical reply? More often than not, I think.
Cheers,
--Karl
_________________
Karl Swedberg
www.englishrules.com
www.learningjquery.com
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