ha ha, u got me...
but, why is that so? aren't there 3 td's each in a "tr" representing index
2?
-GTG
On 8/3/07, Karl Swedberg <[EMAIL PROTECTED]> wrote:
>
> On Aug 3, 2007, at 6:15 PM, Ganeshji Marwaha wrote:
>
> I don't think ur selector is right for selecting the 2nd row, 3rd column.
> It most probably is returning you more elements depending on the number of
> rows u have.
> Eg: if you have 3 rows in your table, then it should return, 1 tr and 3
> td's each representing the 3rd column in every row.
>
>
>
> I don't think that is quite right either, Ganeshji.
>
> Matt's selector ...
>
>
>
> $("tr:eq(1), td:eq(2)")
>
>
>
> ... will select exactly one row (the second one) and exactly one cell (the
> third one).
>
>
> To return "1 tr and 3 td's each representing the 3rd column in every row,"
> he'd have to do something like this ...
>
>
>
> $("tr:eq(1), td:nth-child(3)")
>
>
>
>
>
>
> --Karl
> _________________
> Karl Swedberg
> www.englishrules.com
> www.learningjquery.com
>
>
>
>
>
