Klaus,
Thanks for the hint. very useful !
Jacques
On Jul 28, 2:51 am, Klaus Hartl <[EMAIL PROTECTED]> wrote:
> Jacques Jocelyn wrote:
> > All,
> > Sorry if this question was asked before, but I've been searching but
> > no real answer to this particular topic
>
> > Please consider the following :
> > if I write the following into a file,
> > <div id="radio">
> > <input type="radio" value="0" name="rd1"/>Radio1
> > <br/>
> > <input type="radio" value="1" name="rd1"/>Radio2
> > </div>
>
> > I save the file and
> > use the following code :
> > $(document).ready(function(){
> > $("//[EMAIL PROTECTED]'optionRadio']").change(function(){
> > alert ("optionRadio is changed" + $(this).val());
> > });
> > )}
>
> > this works fine.
>
> > Now if I generate the same content though an Ajax request and write
> > the result to a dynamic div, such as :
> > // Ajax request
> > $("//items/item", xml).each(function(){
> > output+="<br><input type='radio' name='rd1' '" value='" + $('id',
> > this).text()+"' />" +$('description', this).text();
> > });
> > $("#radio").empty().append(output);
>
> > no success; my Alert request never appears
>
> > How can you access to the content id created dynamically with jquery ?
> > Is there a command to refresh the dom document ?
> > thank you
> > Jacques
>
> Jacques,
>
> here's a nice tutorial that should
> help:http://docs.jquery.com/Tutorials:AJAX_and_Events
>
> --Klaus
