> > > From: weepy
> > >
> > > $s = function(s) {
> > > p = s.replace(/#{/g, "' + eval(").replace(/}/g, ") + '")
> > > p = "'" + p + "'"
> > > return eval(p)
> > > }
> > >
> > > a="Jonah"
> > > b=30
> > >
> > > $s("#{a} is #{b} years old")
> > > ==> "Jonah is 30 years old"
> > From: Michael Geary
> > Sorry to be a party pooper, but what happens if you call $s from
> > inside a function, using replacement variables that are
> > local to that function? How will the "eval" see those variables?
> From: Stephan Beal
> You can, to the best of my knowledge, eval code created in
> your local scope, referencing vars created in your scope.
>
> For some details, see:
>
> http://blog.zimki.com/tomi/2006/08/07/javascript-eval
>
> "What the eval method does is evaluate the passed string as
> JavaScript in the context of the Object upon which it is called."
Right, that was exactly my point. The eval function is being called inside
the $s function, so it won't see local variables in a different function.
For example, this won't work:
function test() {
a = "Jonah";
b = 30;
alert( $s("#{a} is #{b} years old") );
}
-Mike
