Chris,
Can you put together a simplified example page. I feel like I'm only
getting part of the picture.
Mike
On 7/16/07, Chris <[EMAIL PROTECTED]> wrote:
Any ideas?
On Jul 15, 12:07 pm, Chris <[EMAIL PROTECTED]> wrote:
> Thank you for the reply mike! I added this to my script:
> $(document).ready(function() {
> // bind 'myForm' and provide a simple callback function
> $('#myForm').ajaxForm(function() {
> $('#thankyou').show('slow');
> $('#newcomment').hide('fast');
> $('#newestcomment').show('slow');
>
> });
> });
>
> and did this with the div:
> <div id="newestcomment" style="display:none;">
> <a href="#"><? echo $_POST["name"]; ?></a><? echo $_POST["comment"]; ?
>
> </div>
> It did not seem to pull the data from post, but it does add another
> space for a comment. The way my form is processed is it send the post
> info to comment.php and that adds it to the database. How do i have
> the jquery talk to the php. I tried using a get from an external php
> page that pulls the latest comment from the database but I didn't know
> where to go after that.
> Thank you!
> -Chris
>
> On Jul 15, 6:06 am, "Mike Alsup" <[EMAIL PROTECTED]> wrote:
>
> > Sorry, I'm meant the formatted *comment*. When a comment is posted,
> > return something like this from the server (filling in the correct
> > info as appropriate):
>
> > <div class="oddcomment">
> > <p><a href="#">author name here</a></p><p>Comment text here</p>
> > </div>
>
> > Mike
>
> > On 7/15/07, Chris <[EMAIL PROTECTED]> wrote:
>
> > > Thank you for the reply mike,
> > > Unfortunately I don't understand how I could use this? What is the
> > > formatted column? I think i understand that you would be running this
> > > code $('#comments h1') after the (data) for the form is complete.
>
> > > On Jul 13, 4:17 am, "Mike Alsup" <[EMAIL PROTECTED]> wrote:
> > > > Chris,
>
> > > > Why don't you return the formatted column when it is posted. Then you
> > > > could do something like this:
>
> > > > $(document).ready(function() {
> > > > $('#myForm').ajaxForm(function(data) {
> > > > $('#thankyou').show('slow');
> > > > $('newcomment').hide();
> > > > $('#comments h1').after(data);
> > > > });
>
> > > > });
>
> > > > Mike
>
> > > > On 7/13/07, Chris <[EMAIL PROTECTED]> wrote:
>
> > > > > Hello everyone,
> > > > > I'm a bit of a noob to this whole AJAX thing so you'll have to forgive
> > > > > me. I've setup a blog, using jQuery the comments are added to mysql
> > > > > using this form plugin (http://www.malsup.com/jquery/form/#getting-
> > > > > started). Posting the comments work great, I was even able to add in
> > > > > a confirmation saying "Thank you for posting". My dilemma is showing
> > > > > the new comment on the page without refreshing. Here is the page to
> > > > > test it: (http://www.iphoneappr.com/index.php?post=48). I was
> > > > > thinking I could do a $.get to an external php page that queries
> > > > > mysql with the most current post and put it in a specific div on the
> > > > > page.
> > > > > Here is the function for the form.
>
> > > > > <script type="text/javascript">
> > > > > // wait for the DOM to be loaded
> > > > > $(document).ready(function() {
> > > > > // bind 'myForm' and provide a simple callback function
> > > > > $('#myForm').ajaxForm(function() {
> > > > > $('#thankyou').show('slow');
> > > > > $('#newcomment').hide('fast');
>
> > > > > });
> > > > > });
>
> > > > > </script>
>
> > > > > Thank you for any help! This is driving me nuts!!!!!
