You don't have to do anything...that would be the default behavior.
Your code starts the animation, and while the animation occurs, the
code doesn't stop, it keeps executing. (GTG says this in the 1st
paragraph.)
RH
On Jul 5, 2007, at 11:24 PM, eddy wrote:
Thank you!
But you only explain a fact to me. I hope you will tell me how to do
some logic while animation is in progress!
On 7月6日, 上午2时59分, "Ganeshji Marwaha" <[EMAIL PROTECTED]>
wrote:
I guess, the animation process happens behind the scenes. So, if you
want to do some logic while animation is in progress, all you need to
do is to add it to the next line after the animation code.
But, if your requirement is to do some logic after the animation
ends,
then you will have to supply a callback function to the animate
method
and perform that logic in the callback method..
Did i answer your question?
-GTG
On 7/5/07, eddy <[EMAIL PROTECTED]> wrote:
Thank you!
Could you tell me how to do another event while animate?
On 7月5日, 下午12时12分, "Ganeshji Marwaha" <[EMAIL PROTECTED]>
wrote:
select both and animate... like this...
$("#first, #second").animate(...);
I believe john once said that, the same timer is used for all the
elements
if specified this way... so, you might not have problems with
smoothness..
-GTG
On 7/4/07, eddy <[EMAIL PROTECTED]> wrote:
There're two divs which have the same position,
<div id='first' style='left:0px,top:0px,width:100px,height:
100px'/>
<div id='second' style='left:0px,top:0px,width:100px,height:
100px'/>
Is there a method to move them smoothly at the same time.
below is not good:
$('#first').animate({left:'50px',top:'100px'},1000);
$('#second').animate({left:'50px',top:'100px'},1000);
