so, for example, if your code is:
<div id="btcontrole">
<span id="span1">hi</span>
<span id="span2">bye</span>
<Table>
...table info...
</table>
</div>
Your jquery object $("#btcontrole") only contains one element, so the
each() only works on it. If you wanted to have a jquery object that
consists of the spans you would use $("#btcontrole span"), or if you
wanted the table to be included:
$("#btcontrole").children()
$("#btcontrole span").each(function(){alert($(this).attr('id'))})
result:
span1
span2
On Jul 3, 3:04 pm, Alexsandro_xpt <[EMAIL PROTECTED]> wrote:
> Hellow???
>
> Somebody help me?
