You don't have any chain to continue with after the attr() call!
You might try this instead ...
$('#image_holder').fadeOut(
"slow"
, function(){
$('#myImage').attr('src',imageid[activeImage]);
$('#image_holder').fadeIn("normal");
}
);
juliandormon wrote:
>
> Thanks for your help. Here's what I'd like to do:
>
> Fade image out, then swap it's src, then fade the new image back in.
>
> I can't seem to continue the chain after I swap the image for some - no
> errors either.
>
>
> Here's my code:
> $('#image_holder').fadeOut("slow",
> function(){$('#myImage').attr('src',imageid[activeImage],
> function(){$('#image_holder').fadeIn("normal")} );});
>
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