A cursory reading of your code looks ok ... stemming shouldn't be an issue
as long as your measure of success is comparing docs that match your
orriginal query with the counts you get out.
What i mean by that is that any stemming should have already been taken
care of when your query object was constructed (either by you manually, or
by QueryParser). the direct equals comparisons you are dong should be
fine.
have you tried adding logging of the raw term field/text and the freq
counts you get back to see if that helps you spot the problem?
: Date: Mon, 6 Feb 2006 14:34:05 -0800
: From: Dmitry Goldenberg <[EMAIL PROTECTED]>
: Reply-To: java-user@lucene.apache.org
: To: java-user@lucene.apache.org
: Subject: How to get mapping of query terms to number of their occurrences
: in a doc?
:
: Given a query, I want to be able to, for each query term, get the number of
occurrences of the term. I have tried what I'm including below and it does not
seem to provide reliable results. Seems to work fine with exact matching but
as soon as stemming kicks in, all bets are off as to value of the number of
occurrences returned.
:
: Any ideas, anyone? Can this be written in a simpler and/or more efficient
way?
: Thanks -
:
: int totalOccurrences = 0;
:
: reader = IndexReader.open(getDirectory(indexDirPath));
: HashSet terms = new HashSet();
: query.extractTerms(terms);
:
: TermFreqVector[] tfvs = reader.getTermFreqVectors(docId);
: if (tfvs != null) {
:
: // For each term frequency vector (i.e. for each field)
: for (int i = 0; i < tfvs.length; i++) {
: String field = tfvs[i].getField();
: String[] strTerms = tfvs[i].getTerms();
: int[] tfs = tfvs[i].getTermFrequencies();
:
: if (strTerms != null) {
:
: // For each term in the query
: for (Iterator iter = terms.iterator(); iter.hasNext();) {
:
: Term term = (Term) iter.next();
: // For each term in the vector
: for (int j = 0; j < strTerms.length; j++) {
:
: // If found the query term among the vector terms
: if (field.equals(term.field()) &&
strTerms[j].equals(term.text())) {
:
: // Add the term frequency to the total
: totalOccurrences += tfs[j];
:
: }
: }
: }
: }
: }
: }
:
-Hoss
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