On Tue, 2010-04-06 at 12:54 -0400, Richard Barnes wrote: > > Thanks so much for the detail. It has helped greatly. > > I did take a look at NIST SP 800-56A section 5.6.2.4 for validating > > the > > public value. I am in learning mode, so I found the 2nd step > > confusing... > > 1. Verify that 2 <= y <= p - 2 > > 2. Verify that y^q = 1 (mod p) > > > > Are the parenthesis around "mod p" correct? This is how it is in the > > NIST doc. > > > Yes, the parens are correct. That's just a more traditional notation > for modular equivalence: > > A = B (mod p) > > is the same as saying (in C notation) > > A % p == B % p > > So in your case you would want to check: > > y^q % p == 1 >
Thanks so much!!! This definitely cleared it up for me! :-) regards, Joy _______________________________________________ IPsec mailing list IPsec@ietf.org https://www.ietf.org/mailman/listinfo/ipsec
