Am Mittwoch, den 08.02.2017, 14:16 +0100 schrieb Nikita Popov: > On Wed, Feb 8, 2017 at 2:02 PM, Torsten Rosenberger <rosenberger@taow > eb.at> > wrote: > > > > > Hello > > > > prehistory: > > i tried to use php_str_to_str function to replace some character > > insteed of use call_user_func with str_replace > > > > in ext/standard/string.c > > PHPAPI zend_string *php_str_to_str(char *haystack, size_t length, > > char > > *needle, size_t needle_len, char *str, size_t str_len); > > > > so i expect a zend_string as result ? > > but when i build i got a warning: assignment makes pointer from > > integer > > without a cast > > > > buf = php_str_to_str(value,strlen(value),"y",1,"J",1); > > ^ > > buf is: zend_string *buf; > > When buf is: int buf; i got no warning. > > > > i found 2 examples which looks like i have done > > ext/standard/var.c > > win32/sendmail.c > > > > You probably forgot to include the header declaring this function. If > C > does not have the declaration for a function, it assumes that it > returns > int. > thank's cannot see the wood for the trees
know it works but with buf = php_str_to_str(value, value_len, "'", 1, "\\x27", 4); i get a segfault buf = php_str_to_str(value, value_len, "'", 1, "\\x2", 3); works but not as i like i want to build a js escape function <script type='javascript'></script> should become <script type=\x27javascript\x27></script> an so on BR/Torsten -- PHP Internals - PHP Runtime Development Mailing List To unsubscribe, visit: http://www.php.net/unsub.php
