On 18/09/15 16:35, Rowan Collins wrote: >> exists() has a place in SOME coding >> styles which does not require to find the 'NULL' some other way to avoid >> the potential notice! > > exists() would not be a way of avoiding the notice. exists() would be a > way of distinguishing an extra state, quite separate from null. > > If what you want to write is "if ( ! exists($foo) || is_null($foo) ) { > ... }" then that is exactly what "if ( isset($foo) )" will give you, > without any notices whatsoever.
NO what I want is if ( exists($foo) ) { is_null($foo) { build uninitialised field } else { build initialise with ($foo) } } isset($foo) only allows { build initialise with ($foo) } and the NULL state is missed with no way of detecting it cleanly if the $foo does in fact not exist. -- Lester Caine - G8HFL ----------------------------- Contact - http://lsces.co.uk/wiki/?page=contact L.S.Caine Electronic Services - http://lsces.co.uk EnquirySolve - http://enquirysolve.com/ Model Engineers Digital Workshop - http://medw.co.uk Rainbow Digital Media - http://rainbowdigitalmedia.co.uk -- PHP Internals - PHP Runtime Development Mailing List To unsubscribe, visit: http://www.php.net/unsub.php