Levi, It's my understanding that the "type variable" is a member of the instance and not of the class. In at least java, generics are unavailable in static context[1] though they can be specifically defined on the static method itself[2].
[1] http://stackoverflow.com/questions/936377/static-method-in-a-generic-class [2] https://docs.oracle.com/javase/tutorial/extra/generics/methods.html On Fri, Sep 11, 2015 at 8:28 AM Levi Morrison <le...@php.net> wrote: > On Thu, Sep 10, 2015 at 5:12 PM, Ben Scholzen 'DASPRiD' > <m...@dasprids.de> wrote: > > Hi Dennis, > > > > thanks for your feedback, see my answers below: > > > >> 1. static methods: > >> > >> class Foo<T> { > >> public static function test() { > >> } > >> } > >> > >> how can I call the method: > >> a) Foo::test() > >> or > >> b) Foo<int>::test() > >> > >> in case b), would the generic methods not be a duplication? > > > > > > Case a) is correct here. A static method is not in the context of an > > instance, so it doesn't know about the class boxing by itself. > > I think b would be correct. Can you explain this rationale a bit more? > > -- > PHP Internals - PHP Runtime Development Mailing List > To unsubscribe, visit: http://www.php.net/unsub.php > >
