On 14 March 2015 at 02:50, Rasmus Lerdorf <ras...@lerdorf.com> wrote:
> The problem there is what does "without dataloss" mean? At which precision do 
> you consider there to be no dataloss?
>
> -Rasmus

"without dataloss" would mean you can go from typeA -> typeB -> typeA'
and typeA === typeA'

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