Hi again,
> On 22 Jan 2015, at 23:47, Larry Garfield <la...@garfieldtech.com> wrote:
>
> Assuming it's accurate and I'm understanding you correctly, I think the
> following would be a sufficient statement for the RFC:
>
> -----
> The behavior of this operator with mixed types is such that the following two
> snippets produce the exact same result in all cases:
>
> return $a <=> $b;
>
> if ($a > $b) {
> return -1;
> }
> elseif ($a < $b) {
> return 1;
> }
> else {
> return 0;
> }
> -----
>
> Or maybe that's implicit in the existing link, I'm not sure. (Now that I
> read it over again.) Basically, in order to understand the more esoteric type
> juggling that may occur you'd need to mentally expand it to its "uncompressed
> form", for which the rules are already defined (if possibly quirky in some
> cases).
Yes, that’s correct. Although it would be more accurate to say that ($a < $b)
is just ($a <=> $b === -1), ($a > $b) is just ($a <=> $b === 1) and similar
things for >= and <=, as that’s how the comparison operators work internally
(with the exception of == which also has a fast case).
I think I’ll add something along those lines to the RFC.
Thanks.
--
Andrea Faulds
http://ajf.me/
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