Hi! > You throw an error. Just as plenty of functions already can’t handle > ridiculously large integer arguments.
The problem is, if you function can handle the int range and you checked for is_int() and everything worked fine - now it's broken because is_int() no longer implies fixed range and there's no way to check if you're dealing with fixed-range number or infinite-range number. > No, it does: There are now integers, and objects that represent large > integers, which behave differently. IS_INT and IS_BIGINT would necessarily behave differently too - since some functions may support both and some only integers. Again, no change here. -- Stanislav Malyshev, Software Architect SugarCRM: http://www.sugarcrm.com/ -- PHP Internals - PHP Runtime Development Mailing List To unsubscribe, visit: http://www.php.net/unsub.php
