On Mon, Jul 14, 2014 at 1:14 PM, Alain Williams <a...@phcomp.co.uk> wrote:
> On Mon, Jul 14, 2014 at 06:09:22PM +0100, Andrea Faulds wrote:
> >
> > On 14 Jul 2014, at 18:01, Alain Williams <a...@phcomp.co.uk> wrote:
> >
> > > But if you have:
> > >
> > > function foo(int $a) {
> > > ...
> > > $a = 3 / 2;
> > > }
> > >
> > > What do you expect $a to contain ? I would suggest integer 1.
> >
>
I would have expected 1 - since it appears, from the code, that $a should
> only contain integers.
What about the current type hinting we have, then?
function foo(Bar $a) {
$a = 3 / 2;
}
Perfectly OK. Why would we treat scalars any different?
