Hi!

> I'm at a bit of a loss as to why Laruence is claiming that allowing
> closures to implicitly access variables in the outer scope requires
> duplicating the symbol table.

Because variables need to be stored somewhere after the parent function
exits.

> Is there any technical reason why it's not possible for scopes to retain a
> pointer to their parent scopes so variables can be looked up that way?

Because the parent scope will be gone by the time closure is called.
Unless we retain a copy of it - which in most cases is very expensive
and impractical - you usually don't need all variables from parent scope
- you need 1-2 of them, keeping all of them linked to the closure - and
thus not freed until closure ceases to exist - would be very expensive.
Declaring shared variables explicitly is a trade-off allowing you to not
keep all the variables in case you do not need them.
-- 
Stanislav Malyshev, Software Architect
SugarCRM: http://www.sugarcrm.com/
(408)454-6900 ext. 227

-- 
PHP Internals - PHP Runtime Development Mailing List
To unsubscribe, visit: http://www.php.net/unsub.php

Reply via email to