> Or operator-overlading to the rescue? :-)
Not quite. Especially because with operator overloading done at this
level (how it would be implemented in PHP) it's almost impossible to
make it consistent:
class string {
public function overload+($mixed) {
return $this->value + $mixed;
}
}
class Integer {
public function overload+($mixed) {
return $this->value + $mixed;
}
}
$int = new Integer(5);
$string = new String("5");
echo $int + $string; // 10
echo $string + $int; // 55
While I like the concept of overloading, I don't really think it's
solvable in a consistent enough manner that it would work here.
On Sun, Feb 26, 2012 at 11:12 AM, Stefan Neufeind <neufe...@php.net> wrote:
> On 02/26/2012 04:48 PM, Anthony Ferrara wrote:
>>> I have to say, it doesn't get work, thinking this:
>>>
>>> $mixed1 = new Interger(2);
>>> $mixed2 = new Interge(3);
>>> $guess_what_type_is = $mixed1 + $mixed2;
>>>
>>> thanks
>>
>> That one is actually pretty straight forward. Since `+` is a numeric
>> operation (with the one exception of array + array), it would call
>> castTo('numeric') on both. Then, the normal type rules would take
>> over. So if it returned an int, the result would be int(5). If it
>> returned a float, it would be float(5)...
>
> Or operator-overlading to the rescue? :-)
>
>
> (Okay, I know that idea has been burried a long time ago - but might
> come in hand here as well.
> http://bugs.php.net/bug.php?id=9331
> http://pecl.php.net/package/operator
> )
>
>
> Regards,
> Stefan
>
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