Hi,

On Fri, 2011-08-12 at 15:48 +0200, Ferenc Kovacs wrote:
> if we would both provide the foo_bar and foo.bar:
> 
> - if your code expects foo.bar to be foo_bar, it's there.
> - if you expect foo.bar, it's also fine.
> - if you did a workaround in the past (parse the query string
> manually), that would also work, in the worst case, you would
> overwrite the foo.bar with the same value.

... and we make it complicated for everybody iterating over the array to
do some work on all elements.

johannes



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