Peter Danenberg pisze:
Quoth Justin Martin on Pungenday, the 30th of Discord:
If I recall correctly, you can use the 'use' keyword.
Thanks, Justin; that occurred to me, too. But the following results in
"Notice: Undefined variable: factorial":
$factorial = function($n) use ($factorial) {
if ($n == 1)
return 1;
else
return $n * $factorial($n - 1);
};
print $factorial(3);
and eventually "PHP Fatal error: Function name must be a string."
This is correct.
See: in the first example you were referencing previously defined $foo
(which at the moment of first reference was NULL). It was only later
replaces with closure itself but it worked because of the reference.
On the other hand when you copy variable you try to use undefined
$factorial (thus the notice). It is because at the moment of "using" the
variable it's undefined. Only later it becomes our closure, however then
it's after evaluation of use.
Although this is probably more a generals topic. The lack of
__FUNCTION__ inside the closure is however something i'd like to hear
more about.
Any word on this from the devs?
TIA,
Marcin
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