For what it matters, the same thing in Java returns the expected result:
Class clazz = Foo.class;
Field fooProp = clazz.getDeclaredField("foo");
fooProp.setAccessible(true);
Bar bar = new Bar();
String value = (String)fooProp.get(bar);
System.out.println(value);
So is this a bug or some weird behavior I just don't understand yet?
Roman
On Apr 4, 2009, at 7:34 AM, Roman Borschel wrote:
Hi,
On Apr 4, 2009, at 1:53 AM, Johannes Schlüter wrote:
On Fri, 2009-04-03 at 22:37 +0200, Roman Borschel wrote:
Given the following simple classes
class Foo {
private $foo = 'value';
public function getFoo() { return $this->foo; }
}
class Bar extends Foo {}
Obviously, given an instance of Bar, say $bar, $bar->getFoo()
returns
'value'.
Now the question: How do I get at this value using reflection, given
an instance of Bar?
class Foo { private $foo = "value"; }
class Bar extends Foo {}
$f = new Foo;
// we have to know the context, as there might be multiple foo
properties
$r = new ReflectionProperty("Foo", "foo");
$r->setAccessible(true);
var_dump($r->getValue($f));
works for me.
johannes
Thanks for your answer. Yes, this works, but here $f is an instance
of Foo, not Bar. When you make it an instance of Bar you get NULL. I
think this is not correct, is it?
Given that we have a ReflectionProperty of class Foo at hand, from
my understanding it should look at an instance of Bar as a Foo and
return the value. Am I missing something?
Regards
Roman
--
PHP Internals - PHP Runtime Development Mailing List
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP Internals - PHP Runtime Development Mailing List
To unsubscribe, visit: http://www.php.net/unsub.php