Hi Johannes,
<?
$o->foo = "foo"; $o->foo(); //Example 1
$o->bar = function(){}; $o->bar(); //Example 2
?>The example 1 must not work, because PHP tries to call $o->foo() as a function, but not $o->foo as description for the function. To make example 2 working, the declaration has to be changed. Thanks, -- (c) Kenan Sulayman Freelance Designer and Programmer Life's Live Poetry http://MyJurnal.tk/
