This code is just a good argument *FOR* type hints. When foo is:
function foo(int $bar) {...}
and you want the code to die if $bar is not integer, then foo($bar) would be
Why would you want it? I wouldn't want my code to die, I would want it
to work.
you have either an int or string representing an integer in $bar, then
foo((integer)$bar) would work just well.
And then how exactly strict typing helps you? You can not control at
development time if everybody uses (integer) or not, since being
interpreted PHP has no static type checking. So only option to find it
out is to leave a minefield behind hoping that testers and not actual
users would be ones who make it blow up. What if testers fail to find it?
--
Stanislav Malyshev, Zend Software Architect
[EMAIL PROTECTED] http://www.zend.com/
(408)253-8829 MSN: [EMAIL PROTECTED]
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