On Wed, May 30, 2007 5:02 pm, stefano federici wrote:
> I trying to find a reason why array functions are not allowed to be
> used as normal arrays. To clarify, I'm allowed to write
>
> $arr = array( "maria", "mario", "luigi", "luisa");
> echo $arr[1];
>
> but I'm not allowed to write
>
> echo array( "maria", "mario", "luigi", "luisa")[1];
>
> In PHP documentation I read that "array" is a language construct, not
> a function. So this may be the reason. But I also tried with
>
> echo (explode (" ", "maria mario luigi luisa"))[1];
>
> and this doesn't work either (even if "explode" is a function). Not
> surprisingly,
>
> $arr = explode (" ", "maria mario luigi luisa");
> echo $arr[1];
>
> does work. So, if I can straightforwardly divide by, say, 2 the
> integer output by a function, why shouldn't I be allowed to
> straightforwardly use the array output by a function?
>
> This is not something completely weird that I'm asking. In Visual
> Basic (that I know mustn't be the most loved programming language for
> PHP users) you can say
>
> print array( "maria", "mario", "luigi", "luisa")(1)
>
> Maybe is THIS the reason why it doesn't work in PHP? ;-)
>
> Thanks for your consideration and helpIt was discussed last month, but as I recall, some nasty "what if" scenarios cropped up, and nobody came up with a reasonable way to do this... -- Some people have a "gift" link here. Know what I want? I want you to buy a CD from some indie artist. http://cdbaby.com/browse/from/lynch Yeah, I get a buck. So? -- PHP Internals - PHP Runtime Development Mailing List To unsubscribe, visit: http://www.php.net/unsub.php
