Stanislav Malyshev wrote:
I'd say expression(f()[1]) means $tmp = f(); expression($tmp);
unset($tmp); which here means:
$tmp = foo();
$tmp[1] = 4;
unset($tmp);
which is meaningless but should work. IIRC the engine can make free's at
the end of expression, so it shouldn't be big problem. Actually, any
assignment to it if it's not returned by-ref is meaningless, but
syntactically ok.
foo() = 4; results in:
Fatal error: Can't use function return value in write context in test on
line 12.
foo()[1] = 4; should do the same.
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