Rick Widmer wrote:
D. Dante Lorenso wrote:
Eric,
This reply is too basic and is not the answer. The problem is more
complex then you have grasped.
function ifsetor() {
$args = func_get_args();
$count = count( $args );
for( $i=0; $i<$count; $i++ ) {
if isset( $args[ $i ] )) {
return $args[ $i ];
}
return false;
}
No, that doesn't address the problem. See this:
---------- 8< -------------------- 8< -------------------- 8< ----------
<pre>
<?php
function ifsetor() {
$args = func_get_args();
$count = count($args);
for ($i=0; $i<$count; $i++) {
if (isset($args[$i])) {
return $args[$i];
}
}
return false;
}
print ifsetor($x, $y, $z, "dante")."\n";
?>
</pre>
PHP Notice: Undefined variable: x in .../ifsetor.php on line 13
PHP Notice: Undefined variable: y in .../ifsetor.php on line 13
PHP Notice: Undefined variable: z in .../ifsetor.php on line 13
---------- 8< -------------------- 8< -------------------- 8< ----------
See my post regarding a specification for 'filled()' as a function. An
important feature is that warnings about unset variables should not
occur. Your suggestion does not qualify. This problem can not be
solved in userspace.
Dante
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