Hello Jochem,
Friday, December 23, 2005, 1:28:36 PM, you wrote:
> if I have an object with a given base class and it
> has an object as a property which has the same base class
> should I or should I not be able to call a protected method
> on the contained (delegated) from the first (container) object?
of course not it is a different object. If we had subclasses this
would be different.
> currently I am not able to do what I thought should work, below
> is an example which hopefully makes it clear what i'm going on about.
Just to make this clear: your code as given below must fail because
it violates visibility/inheritance rules.
> if this behaviour is expected I'd be very grateful if anyone
> could shed some light on why.
The problem is that we neither have 'friend' which would help you
here nor do we have a second visibility rule set (however no other
language supports that) and also programming languages do support
grant models like databases do.
> kind regards,
> Jochem
$>> php -r '
> abstract class A {
> function test() { $this->doit(); }
> protected function doit() { echo "A\n"; }
> }
> class B extends A {
> protected function doit() { parent::doit(); echo "B\n"; }
> }
> class C extends A {
> function __construct() { $this->delegate = new B; }
> protected function doit() { $this->delegate->doit(); echo "C\n"; }
> /*
> the problem can be solved here by chaing the preceeding line of code to:
> protected function doit() { $this->delegate->test(); echo "C\n"; }
> but that does not solve the realworld issue I had regarding this :-)
> */
> }
> $b = new B; $c = new C;
> $b->test();
> $c->test();
> '
> A
> B
> Fatal error: Call to protected method B::doit() from context 'C' in Command
> line code on line 5
Best regards,
Marcus
--
PHP Internals - PHP Runtime Development Mailing List
To unsubscribe, visit: http://www.php.net/unsub.php
