Hello,
this issue was already cleared as bogus
safe_emalloc already takes care of the one extra byte that should get added.
safe_emalloc does allocate param1 * param2 + param3 bytes
result = (unsigned char *)safe_emalloc(((length + 2) / 3) * 4, sizeof(char), 1);
would become
result = (unsigned char *)safe_emalloc(((length + 2) / 3) * 4 + 1, sizeof(char), 1);
Stefan
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