On 20.05.2021 19:05, Nikita Popov wrote: >> $fn = &Foo::myFunc; >> > Unfortunately, this syntax is trivially ambiguous. "$fn = &$this->myFunc" > is currently already interpreted as a reference assignment of the property > $this->myFunc.
could that be just fn(sth)? I mean without the => part. $fn = fn($this->myFunc); $fn = fn(myFunc); $fn = fn(Foo::myFunc); and then something like this $partial = fn(Foo::myFunc)[?, 42]; or $partial = fn(Foo::myFunc, ?, 42); My earlier idea was that actually cloning a callable could convert it to a Closure, but I'm not sure now: $fn = clone $this->myFunc; or is this a heresy? ;) -- Aleksander Machniak Kolab Groupware Developer [https://kolab.org] Roundcube Webmail Developer [https://roundcube.net] ---------------------------------------------------- PGP: 19359DC1 # Blog: https://kolabian.wordpress.com -- PHP Internals - PHP Runtime Development Mailing List To unsubscribe, visit: https://www.php.net/unsub.php
