Well, I think this answer the first question. Since consistency is king, why not just applying the same behavior than without spread operator? What do you think ?
De : Côme Chilliet<mailto:come.chill...@fusiondirectory.org> Envoyé le :mercredi 3 juin 2020 17:02 À : internals@lists.php.net<mailto:internals@lists.php.net> Objet :Re: [PHP-DEV] RFC proposal: Spread Operator for Array Destructuring Assignment Le Wed, 3 Jun 2020 11:46:00 +0200, Nikita Popov <nikita....@gmail.com> a écrit : > To give a tl;dr of existing discussions on the topic: > > $foobar = [2 => 2, 1 => 1, 0 => 0]; > [$foo, ...$bar] = $foobar; > // What is the result? > > Introducing this feature is primarily a matter of coming up with a > satisfactory answer to the above question. (There is an existing > constraint that $foo must be equal to 0 in this case, not 2.) Well, I guess it should behave exactly the same as: $foobar = [2 => 2, 1 => 1, 0 => 0]; [$foo, $foo2, $foo3] = $foobar; $bar = [$foo2, $foo3]; for consistency, no?
