On Thu, 2004-02-26 at 08:13, Andi Gutmans wrote: > Please let me know when you are able to reproduce it. > The stacktrace doesn't tell me much. > Thanks, > Andi
Got it:) <?php class Foo { public $attributes= array(); function export() { foreach ($this->attributes as $name => $attr) { } } } $f= new Foo(); $f->export(); ?> - Timm -- PHP Internals - PHP Runtime Development Mailing List To unsubscribe, visit: http://www.php.net/unsub.php